Three-Phase Motor Calculator

The two motor questions asked on every plant walkdown: "it's drawing this current — what load is it actually carrying?" and its twin, "this pump needs this shaft power — what current should I expect?" Both directions, plus torque.

The Calculation, Explained

Where the √3 comes from

In a balanced three-phase system each phase carries Vph × Iph × cos φ of real power. Line voltage is √3 times phase voltage (the phases sit 120° apart, and the geometry of that phasor triangle is the whole story), so with line quantities:

Pin (kW) = √3 × Vline × Iline × cos φ / 1,000   |   Pshaft = Pin × η
T (Nm) = 9,550 × Pshaft (kW) / N (rpm)    — the constant is 60,000 / 2π: power = torque × angular speed

Assumptions and applicability

Worked example (the defaults above)

A 400 V motor drawing 85 A at PF 0.86: input = 1.732 × 400 × 85 × 0.86 = 50.6 kW; at 93% efficiency the shaft delivers 47.1 kW, which at 1,480 rpm is a torque of 47.1 × 9,550 / 1,480 = 304 Nm, on 58.9 kVA of apparent power. If the driven pump's duty only accounts for 38 kW, the missing 9 kW is a finding — throttled valve, worn internals passing flow, or a motor oversized into poor efficiency — before it is a mystery.

References

IEC 60034 (rotating electrical machines — rating and performance); NEMA MG 1 (motors and generators, incl. unbalance derating).