Fuel Flow Calculator

Given a plant's output and heat rate, how much fuel must be flowing? This is the arithmetic a performance engineer runs against the fuel metering on test day — before believing anyone's efficiency claim.

The Calculation, Explained

The derivation

Everything follows from one balance: fuel energy in = electrical energy out / efficiency, and heat rate is efficiency in disguise.

Fuel thermal power (MW) = Pnet × HR / 3,600
Mass flow (kg/s) = Fuel thermal power (kJ/s) / LHV (kJ/kg)

Volume flow needs the gas density at the reference state. This calculator uses normal conditions (0 °C, 1.01325 bar), where air density is 1.293 kg/m³, so ρgas = SG × 1.293:

Volume flow (Nm³/h) = Mass flow (kg/h) / (SG × 1.293)

MMSCFD converts the daily volume to cubic feet (1 ft³ = 0.0283168 m³); MMBTU/h converts thermal power at 1 MW = 3.41214 MMBTU/h.

Assumptions and applicability

Worked example (the defaults above)

An 850 MW plant at 9,850 kJ/kWh: thermal input = 850 × 9,850 / 3,600 = 2,325.7 MW thermal. At LHV 49.0 MJ/kg, mass flow = 2,325,700 / 49,000 = 47.5 kg/s (170.9 t/h). At SG 0.60 (ρ = 0.776 kg/Nm³): ≈ 220,000 Nm³/h, i.e. ≈ 187 MMSCFD, or 7,936 MMBTU/h. If the station meter reads far from these numbers at this load, either the meter, the heat rate, or the LHV is wrong — and finding out which is exactly what test day is for.

Practitioner's note. Run this calculation before the test, at the expected test load, and write the expected fuel flow on the test log sheet. A meter that disagrees is discovered in the first hour, while it can still be fixed — not in the report, three weeks later.

References

ASME PTC 46 (test boundary and fuel measurement); ISO 6976 (heating values from composition — see the companion Gas Heating Value & Wobbe Index calculator for the LHV and SG of your actual gas).